Question

A solution of 25% water and 25% ethanol and 50% acetic acid by mass calculate mole fraction of each component

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Answer 1

Answer:

Let the mass of solution is 100g

Then, mass of H

2

O=25g

mass of ethanol =25g

mass of acetic acid =50g

Number of moles of water =

18g/mol

25g

=1.4

Number of moles of ethanol =

46g/mol

25g

=0.54

Number of moles of Acetic acid =

60g/mol

50g

=0.8

Total number of moles =(1.4+0.54+0.8)=2.74

Now, mole fraction of water =

2.74

1.4

=0.51

mole fraction of Ethanol =

2.74

0.54

=0.197

mole fraction of acetic acid =

2.74

0.8

=0.291

Explanation:

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Answer 2

ANSWER

Let the mass of solution is 100g

Then, mass of H2O=25g

mass of ethanol =25g

mass of acetic acid =50g

Number of moles of water =

$\frac{25}{18} = 1.4$

Number of moles of ethanol= 25/46 = 0.54

Number of moles of Acetic acid = 50/60 = 0.8

Total number of moles =(1.4+0.54+0.8)=2.74

Now, mole fraction of water = 1.4/2.74 = 0.51

mole fraction of ethanol = 0.54/2.74 = 0.19

mole fraction of acetic acid = 0.8/2.74 = 0.291

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