A solution of 27 gallons of 9 gallons of pure acid. How much water in gallons, should be added to produce a 25% solution of acid?
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Given: 27 gallons solution, 9 gallons of Pure acid. We need to find: How much water in gallons,should be added to produce a 25 percent solution of this acid? Water=36-27 = 9 gallons.
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