Question

A solution of 3.795g of sulphur in 100g of disulphide(b.p 46.30°C enthalpy of vaporization=6400 cal per mole) boils at 46.66°C what is formula of sulphur molecule in the solution

Answer 1

Answer:

number of mole of sulphur =n

molality =

100g

n

=

0.1kg

n

=100

ΔT

b

=K

b

m

T

b

o

−T

b

=K

b

m

319.81−319.45=2.42×10n

n=

24.2

0.36

Let molar mass of sulphur M

M

3.795

=

24.2

0.36

M=

0.36

3.795×24.2

=255.19

Atomic mass of sulphur = 32

total number of atom of sulphur =

32

255.19

≈8

Molecule of sulphur = 58

Explanation:

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