A solution of 44 litres contain acid and water in the ratio5:6.If 4 litre of solutions is replaced with acid then what is the quantity of acid in new mixture?
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Step-by-step explanation:
Acid:water=5:6
Given solution =44
Amount of acid=(5/11)*44----->20
Amount of water=(6/11)*44----->24
Now 4 liters are removed hence the solution becomes =40
Now we have to calculate the amount of acid in the 40 liters
Amount of acid=(5/11)*40----->18.18
As given in the question 4 extra liters of acid are added and hence the solution finally consists of -------> 18.18+4=22.18 liters.
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