Question

A solution of 50 cm3 hydrochloric acid has a ph of 4. What is the final ph if 450cm3 of water is added?

Answer 1

ANSWER

: If the pH is 4, then [H+] is 1x10^-4. Therefore,

(50 ml)(1x10^-4 M) = (500 ml)(x M)

x = 1x10^-5 M

pH = 5

Answer 2

Final pH is 5 if $450cm3$ of water is added

Explanation:

GIven,

• A solution of $50 cm3$ hydrochloric acid has a pH of $4$
• If the pH is 4, then [H+]  hydrogen ion concentration is 1x$10^{-4}$.
• pH :- pH is a measure of acidity and basicity of  water.
• The range of pH is from 0 - 14, where 7 is neutral.
• pH  less than 7 shows acidity, whereas a pH greater than 7 shows base.
• pH is a measure of the amount of hydrogen and hydroxyl ions in the water

       We have to find out the final pH if $450cm3$ of water is added

       Therefore,

        ⇒ ($50 ml$)($1$x$10^{-4}$M) = ($500 ml$)x (M)

        ⇒x = $1$x$10^{-5}$M

         pH = 5

         Final pH is 5 if $450cm3$ of water is added

#SPJ2