Question

A SOLUTION OF 795g Of WATER INITIALLY AT 49°C. CALCULATE THE FINAL TEMPERATURE OF THE SYSTEM IF 2209kj OF ENERGY IS ADDED BY HEAT​

Answer 1

Answer:

100°C as water boil at this pt.

Answer 2

Explanation:

Given A SOLUTION OF 795 g Of WATER INITIALLY AT 49°C. CALCULATE THE FINAL TEMPERATURE OF THE SYSTEM IF 2209 kj OF ENERGY IS ABSORBED BY HEAT

• Now specific heat of water is given by 4.18 J / g degree C
• The specific heat of a substance is the heat required to raise the temperature of 1 g of a substance by 1 degree C.
• Now we have the equation for heat lost or heat gained by a substance and also change in temperature will be
• So q = m . c. ΔT
• Here q = amount of heat
• So m = mass of the solution
• So c = specific heat
• So Δt = change in temperature.
• So we get Δt = q / m . c
•                    = 2209000 J /  795 g  x 4.18 J / g degree C
•                    = 664.74 degree C
• Now change in temperature is the difference between initial and final temperature.
• So Δ T = T final – T initial
• Or T final = T initial + Δ T
•                   = 49 degree C + 664.74 degree C
•                  = 713.74 degree C
•                   = 713 degree Celsius.

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