A SOLUTION OF 795g Of WATER INITIALLY AT 49°C. CALCULATE THE FINAL TEMPERATURE OF THE SYSTEM IF 2209kj OF ENERGY IS ADDED BY HEAT
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Answer:
100°C as water boil at this pt.
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Explanation:
Given A SOLUTION OF 795 g Of WATER INITIALLY AT 49°C. CALCULATE THE FINAL TEMPERATURE OF THE SYSTEM IF 2209 kj OF ENERGY IS ABSORBED BY HEAT
- Now specific heat of water is given by 4.18 J / g degree C
- The specific heat of a substance is the heat required to raise the temperature of 1 g of a substance by 1 degree C.
- Now we have the equation for heat lost or heat gained by a substance and also change in temperature will be
- So q = m . c. ΔT
- Here q = amount of heat
- So m = mass of the solution
- So c = specific heat
- So Δt = change in temperature.
- So we get Δt = q / m . c
- = 2209000 J / 795 g x 4.18 J / g degree C
- = 664.74 degree C
- Now change in temperature is the difference between initial and final temperature.
- So Δ T = T final – T initial
- Or T final = T initial + Δ T
- = 49 degree C + 664.74 degree C
- = 713.74 degree C
- = 713 degree Celsius.
Reference link will be
https://brainly.in/question/3052378
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