a solution of a substance xis used for white washing (1)name the substances xand write its formula (2)write te reaction of the substance x nomed un above the water
Answers
Given :-
5 mol of liquid A and 10 mol of liquid B are mixed to form an ideal solution.
[Pᴀ = 200 mm Hg, Pʙ = 400 mm Hg]
To Find :-
What is the total pressure of the solution.
Formula Used :-
\clubsuit♣ Total Pressure Formula :
\begin{gathered}\mapsto \sf\boxed{\bold{\pink{P_T =\: P^{\circ}_AX_A + P^{\circ}_BX_B}}}\\\end{gathered}
↦
P
T
=P
A
∘
X
A
+P
B
∘
X
B
Solution :-
{\small{\bold{\purple{\underline{\leadsto\: In\: case\: of\: X_A\: :-}}}}}
⇝IncaseofX
A
:−
\begin{gathered}\bigstar\: \: \sf\boxed{\bold{\pink{X_A =\: \dfrac{n_A}{n_A + n_B}}}}\\\end{gathered}
★
X
A
=
n
A
+n
B
n
A
where,
\sf n_An
A
= Number of Moles in liquid A
\sf n_Bn
B
= Number of Moles in liquid B
Given :
Number of Moles in liquid A = 5 moles
Number of Moles in liquid B = 10 moles
According to the question by using the formula we get,
\implies \sf X_A =\: \dfrac{5}{5 + 10}⟹X
A
=
5+10
5
\implies \sf X_A =\: \dfrac{\cancel{5}}{\cancel{15}}⟹X
A
=
15
5
\implies \sf X_A =\: \dfrac{1}{3}⟹X
A
=
3
1
\implies \sf\bold{\green{X_A =\: \dfrac{1}{3}}}⟹X
A
=
3
1
\begin{gathered}{\small{\bold{\purple{\underline{\leadsto\: In\: case\: of\: X_B\: :-}}}}}\\\end{gathered}
⇝IncaseofX
B
:−
\begin{gathered}\bigstar\: \: \sf\boxed{\bold{\pink{X_B =\: \dfrac{n_B}{n_A + n_B}}}}\\\end{gathered}
★
X
B
=
n
A
+n
B
n
B
where,
\sf n_An
A
= Number of Moles in liquid A
\sf n_Bn
B
= Number of Moles in liquid B
Given :
Number of Moles in liquid A = 5 moles
Number of Moles in liquid B = 10 moles
According to the question by using the formula we get,
\implies \sf X_B =\: \dfrac{10}{5 + 10}⟹X
B
=
5+10
10
\implies \sf X_B =\: \dfrac{\cancel{10}}{\cancel{15}}⟹X
B
=
15
10
\implies \sf X_B =\: \dfrac{2}{3}⟹X
B
=
3
2
\implies \sf\bold{\green{X_B =\: \dfrac{2}{3}}}⟹X
B
=
3
2
Now, we have to find the total pressure of the solution :
Given :
Vapour Pressure Of Liquid A = 200 mm Hg
Vapour Pressure Of Liquid B = 400 mm Hg
According to the question by using the formula we get,
\longrightarrow \sf P_T =\: 200 \times \dfrac{1}{3} + 400 \times \dfrac{2}{3}⟶P
T
=200×
3
1
+400×
3
2
\longrightarrow \sf P_T =\: \dfrac{200}{3} + \dfrac{800}{3}⟶P
T
=
3
200
+
3
800
\longrightarrow \sf P_T =\: \dfrac{200 + 800}{3}⟶P
T
=
3
200+800
\longrightarrow \sf P_T =\: \dfrac{1000}{3}⟶P
T
=
3
1000
\longrightarrow \sf\bold{\red{P_T =\: 333.3\: mm\: Hg}}⟶P
T
=333.3mmHg
\therefore∴ The total pressure of the solution is 333.3 mm Hg.
Hence, the correct options is option no (3) 333.3 mm Hg.
Answer:
(2) Write the reaction of the substance X named in (1) above with water. Answer: (1) The solution of the substance used for whitewashing is calcium oxide also called quicklime with chemical formula CaO. ... CaO (s) + H2O (l) → Ca(OH)2(aq)