Question

A solution of alcohol in water has been prepared by mixing 100 ml of alcohol in 300 ml of water. Calculate the volume percentage of the solution

Answer 1

Answer:

volume percent of alcohol= 100/400*100 = 25%

volume percent of water = 300/400*100 = 75%

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Answer 2

$\huge{\textbf{\underline{Mole Concept !!}}}$

Volume of alcohol = 100 ml

Volume of water = 300 ml

Volume of solution will be = ( volume of water + volume of alcohol )

Volume of Solution = (100 + 300)ml

Volume of Solution = 400 ml

Volume percentage :- The ratio of the volume of the solute to the volume of solution expressed as percentage is called volume percentage.

$\left[ \text{Volume Percentage} = \dfrac{\textbf{Volume of solute }}{\textbf{Volume of Solution}}\times 100 \right]$

• Alcohol is present in less amount so it is solute and water is solvent.

$Volume \% = \dfrac{100}{300}\times 100$

$Volume\% = \dfrac{10000}{300}$

$Volume\% = \dfrac{100}{3}$

$\textbf{Volume percentage of solution is 33.3 \%}$

$\large{\textbf{\underline{Useful key points:-}}}$

• Instead of volume we can also express concentration as mass percentage of solute.

• Molarity and Normality of solution changes with change in temperature.