A solution of ammonia has a pH of 11.8. What is the concentration of OH– ions in the solution?
Answers
Answered by
15
pOH=2.2
OH^-=10^-2.2 = 6.31*10^-3 M
hope this can help you
eo01569:
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Answered by
9
Hello dear,
● Answer -
[OH-] = 6.309×10^-3 m
● Explanation -
pH & pOH are related by eqn -
pH + pOH = 14
11.8 + pOH = 14
pOH = 14 - 11.8
pOH = 2.2
Concentration of OH- ions is given by -
pOH = -log[OH-]
[OH-] = antilog(-2.2)
[OH-] = 6.309×10^-3 m
Hence, concentration of [OH-] is 6.309×10^-3 .
Hope this helps you.
Keep asking..
● Answer -
[OH-] = 6.309×10^-3 m
● Explanation -
pH & pOH are related by eqn -
pH + pOH = 14
11.8 + pOH = 14
pOH = 14 - 11.8
pOH = 2.2
Concentration of OH- ions is given by -
pOH = -log[OH-]
[OH-] = antilog(-2.2)
[OH-] = 6.309×10^-3 m
Hence, concentration of [OH-] is 6.309×10^-3 .
Hope this helps you.
Keep asking..
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