A
solution of caustic soda contains 20% NaoH by weight.Taking density of the solution as 1.196kg/l.Find the normality,molarity,and molality of the solution.
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Let x be the mass of solution.
Mass of NaOH= 100x×20
Molar mass of NaOH=40g
∴ Number of moles= ( 10020x)/40= 200x
Now mass of solvent in the solution= x−
100
20x
= 100
80x
∴ Molality=
(80x/100)x/200×1000=6.25M
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