A solution of citric acid C6 H8 O7 in 50 g of acetic acid has a boiling point elevation of 1.76 K. If Kb for acetic acid is 3.07 K kg mol-1, what is the molality of solution?
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Explanation:
Given: Boiling point elevation =ΔTb = 1.76 K
Kb of acetic acid = 3.07 K kg mol-1
Mass of acetic acid = 50 g
To find: Molality of the solution
Formula: ΔTb = Kb m
Calculation: Using formula and rearranging, we get,
m
Tb
Kb
K
K kg mol
mol kgm=△TbKb=1.76K3.07K kg mol-1=0.573 mol kg-1 = 0.573 m
The molality of the solution is 0.573 m.
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