Question

a solution of citric acid C6H8O7 in 50 grams of Acetic acid has a boiling point elevation of 1.76 k .if Kb for Acetic acid is 3.07 k kg per mole .what is the molality of the solution​

Answer 1

Answer:

sorry I am junior student

Answer 2

Answer:

Given,

Boiling point elevation = 1.76 K

Kb = 3.07 K kg per mole

We know that,

Boiling point elevation = Kb x Molality

Therefore,

1.76 = 3.07 x m

m = 0.573

Explanation:

Correct me if I'm wrong.