Chemistry, asked by nirmalmohan1505, 7 months ago

A solution of copper(II) sulphate is electrolysed between two copper electrodes by a current of 10.2 amp
for 62 min at 298K. About 0.1875 mole of copper is dissolved from anode, calculate the amount of copper
deposited from cathode:-

Answers

Answered by magicwander

0

Answer:

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