A SOLUTION OF CUS4 IS ELECTROLYSED USING A CURRENT OF 1.5A FR 10 MIN WHAT IS THE MASS OF CU DEPOSITED AT CATHODE
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A solution of CuSO4 is electrolysed for 10 minutes with a current of 1.5 amperes. What is the mass of copper deposited at the cathode?
t = 600 s
Charge = current x time
= 1.5 A x 600s = 900 C
According to the reaction : Cu2+(aq) + 2e– → Cu(s)
We require 2F or 2 x 96487 C to deposit 1 mol or 63 g of Cu
For 900 C, the mass of Cu deposited =
(
63
g
mol
−
1
×
900
C
)
2
×
96487
C
mol
−
1
=
0
.
2938
g
.
(63 g mol-1 × 900 C)2 × 96487 C mol-1 = 0.2938 g.
t = 600 s
Charge = current x time
= 1.5 A x 600s = 900 C
According to the reaction : Cu2+(aq) + 2e– → Cu(s)
We require 2F or 2 x 96487 C to deposit 1 mol or 63 g of Cu
For 900 C, the mass of Cu deposited =
(
63
g
mol
−
1
×
900
C
)
2
×
96487
C
mol
−
1
=
0
.
2938
g
.
(63 g mol-1 × 900 C)2 × 96487 C mol-1 = 0.2938 g.
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