Question

A solution of glucose (C6H12O6) in water is labelled as 10% by weight. What would be the molality the solution?(Molar mass of glucose =180g mol^-1)

Answer 1

n=moles,W=weight,M=molar mass

Answer 2

Answer:

The molality of the solution is 0.6172 mol/kg.

Explanation:

10% by weight solution of glucose means in 100 g of solution there are 10 g of glucose and 90 g of water.

$Molality=\frac{\text{mass of solute}}{\text{Molar mass of solute}\times \text{Weight of solvent in kg}}$

$m=\frac{10 g}{180 g/mol\times 0.090 kg}=0.6172 mol/kg$

The molality of the solution is 0.6172 mol/kg.