A solution of glucose (c6h12o6) in water is labelled as 10% by weight. What would be the molality of the solution? (molar mass of glucose = 180 g/mol).
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Answer:
molality is 0.6173
Explanation:
Given :
concentration of solution = 10% by mass
(10g glucose and 90 g water)
Molar mass of glucose is 189g
Solution:
Molality = (number of moles of solute/weight of solvent) X 1000
Number of moles = weight / molar mass
= 10/180
= 0.055
Molality = (0.055/90)X1000
= 0.6173
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