Question

A solution of glucose in water is labelled as 10% w/w what would be molarity of solution (Molar mass of glucose = 180{mol}^{ - 1}mol
−1
${mol}^{ - 1}$
​

Answer 1

hi friend,

here is your answer

A solution of glucose in

10% w/w glucose solution corresponds to 10 g glucose present in 100 g of solution which contains 90 g of water.

(i) Molarity is the number of moles of glucose present in 1 kg of water. Number of moles of glucose is the ratio of mass (10 g) of glucose to its molar mass (180 g/mol).

Molality =

180×0.090

10

=0.618 m

Note: 90 g corresponds to 0.090 lg.

(ii) Molarity is the ratio of number of moles of glucose to volume of solution (in L).

Since, denstiy of solution is 1.20 g/mL, the volume of solution is

1.20

100

mL or

1.20×1000

100

L.

Molarity =

180×

1.20×1000

100

10

=0.667 M

(iii) Number of moles of glucose =

180

10

=0.0556

Number of moles of water =

18

90

=5.0

Mole fraction of glucose =

0.0556+5.0

0.0556

=0.011

Mole fraction of water =1−0.011=0.989

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