Question

A solution of glucose is prepared by dissolving 22.5 gram of glucose in 500 ml of water.calculate the molarity of the solution

Answer 1

Answer:

mass of glucose = 22.5g

molar mass of glucose = 180g

no. of moles = 22.5/180 = 0.125

Molarity = no. of moles / volume in L

= 0.125 / 0.5 = 0.25M

Answer 2

Answer:

volume =500ml

molar mass of the solute (mb) = (6×12)+(1×12)+(6×16)= 180

mass of the solute( WB) = 22.5 g

molarity =( 22.5 ×1000)÷(180×500)=0.25 M