Question

A solution of glucose (molar mass 180 gram mol-1) has been prepared by dissolving 25 g of glucose in 1 kg of water Kf for water is 1.86 K Kg mol-1 and Kb for water is 0.52 K kg Mol-1 and vapour pressure of water at 298 K is 0.023 atm.
the vapour pressure of the solution at 298 K will be
(a) 0.0018 atm, (b) 0.0026 atm, (c) 0.0047 atm, (d) 0.0062 atm
The osmotic pressure of the solution at 298 K will be
(a) 3.43 atm, (b) 34.3 atm, (c) 4.36 atm, (d) 43.6 atm
The freezing point depression and freezing point of the solution will be (a) -0.316 K & 272.834 K (b) -0.526 K & 272.624 K (c) -0.152 K & 272.998 K (d) -0.258 K & 272.892 K
The boiling point elevation and boiling point of the solution will be
(a) 0.015 K & 373.165 K (b) 0.027 K & 373.177 K (c) 0.072 K & 373.222 K (d) 0.051 K & 373.201 K
The mass of sodium chloride that should be dissolved amount of water to get the same freezing point or boiling point will be (a) 4.06 g (b) 0.406 g (c) 3.20 g (d) 0.320 g
If on dissolution the same amount of sodium chloride in 1 kg of water the percentage dissociation of sodium chloride in the solution is
(a) 98% (b) 99 % (c) 100 % (d) 101%​

Answer 1

Answer:

hii

Explanation:

तुम जो ग्लूकोस का क्वेश्चन पूछ रहे हो तुम्हें चढ़ावे