A solution of Glucose Of C6 H12 O6 in H2O Given:10gm of Glucose dissolved in H2O and the solution is made to 100cm3 in a volumetric flask. Calculate Molarlity of the solution ?
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Molalityof a solution is defined as the number of moles of solute dissolved per kg of solvent.
C H O
6 12 6
Thus in 100 g solution mass of glucose = 10 g and of water =90 g
Number of moles of glucose =
mass/molar mass
n= 10/ 180= 1/18 mol
Mass of solvent = 90 g= 0.09 kg
Molality, m= (1/18) / 0.09
m= 100/18×9=0.617 molal≈0.6 molal
The molality of a solution of glucose (C H O )
6 12 6
in water is labelled as 10% by weight is 0.617 molal.
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