A solution of h2so4 is 10%(wt/wt).find the mass of h2so4 present in 100ml of solution (densities of solution=1.4g/ml)
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10 percent by volume of H2SO4 means that 10 ml acid in 100 ml solution
volume of H2SO4= 10ml
Volume of water= 90 ml
Density of solution is 1.4 g/cc
mass of aq solution of H2SO4=volume*density= 1.4*100=140g
Mass of water is= 90*1=90g
Mass of solute i.e. H2SO4= 120-90 = 30g
molality means number of moles of solute present in 1 kg solvent .
Hence molality= number of mole of solute/wt.of solvent in kg
number of mole of solute=30/98=.306
Mass of water is= 90*1=90g=.09kg
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