Chemistry, asked by Anureet25, 4 months ago

A solution of H2SO4 is 4.9% by mass. Find molality of solution and mole fraction of H2SO4.

Answers

Answered by maitri1006
1

Explanation:

Strength (g/L) of H

2

SO

4

=

100

4.9

×1000=49

Molarity=

Mol.mass

Strength

=

48

49

=0.5 M

Normality=n×Molarity

n=

Eq.mass

Mol.mass

=

49

98

=2

Normality=2×0.5=1.0

Hence, the H

2

SO

4

solution is 1 N.

Answered by athirapillai02
11

Answer:

hello

Explanation:

Strength (g/L) of H2SO4 = 4.9/100×1000=49

Molarity=strength/mol mass= 49/48=0.5M

Normality=n×Molarity

n= Mol.mass/Eq mass= 98/49=2

Normality=2×0.5=1.0

Hence, the H2SO4 , solution 1 N

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