A solution of HCL has pH = 3 ,is diluted 100 times .What is the pH of the solution?
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Solution:
If pH = 3,then the given sol is acidic and its concentration = 1 × 10^ -3 N
It diluted 100 times then conc = (1 × 10^ -3 N)/100
= 1 × 10^ -5N
So pH = -log(1 × 10^ -5) = 5
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