Question

A solution of hn03 is 70 percentage by strength (v/v) if the density of hn03 is 1.42 g/ml find molarity and Normality​

Answer 1

70% HNO3 ie 70ml HNO3 in 100ml solution

Density of HNO3 = 1.42g/ml

Mass of HNO3 = Density x Volume = 1.42 x 70 = 99.4g

moles of HNO3 = Given mass/Molar mass = 99.4/63 = 1.6 mol

Molarity = 1.6/0.1 = 16 mol/L

Normality = Molarity x n factor = 16 x 1 = 16