Question

A solution of HNO2 is 5% (weigh by weigh) find the mass of HNO3 presant in 100ml of solution (density = 1.4 g/ml)​

Answer 1

AnswEr :

• Mass of HNO₃ present in 100 ml of solution is 7g.

GivEn :

• 5% of $\rm HNO_3$ is dissolved in 100 mL of solution.

• Density = 1.4 g/mL

To find :

• Mass of $\rm HNO_3$ dissolved in 100 mL of solution = ?

Solution :

Let us assume that volume of the solution be x .

Now,

Accordingly density is given,

So,

$\dashrightarrow \sf \ \ \ \rho= \dfrac{M}{V}$

$\dashrightarrow \sf \ \ \ 1.4= \dfrac{100}{x}$

$\dashrightarrow \sf \ \ \ x = \dfrac{100}{1.4}$

$\dashrightarrow \sf \ \ \ { \underline{ \boxed{ \bf{ \blue{x = 71.4mL}}}}} \ \bigstar$

Now,

As we have got the volume(x), which means ,

• 71.4 ml = 5g of HNO₃

$\dashrightarrow \sf \ \ \ 100 = \dfrac{100 \times 5}{71.4}$

$\dashrightarrow \sf \ \ \ 100 = \dfrac{500}{71.4}$

$\dashrightarrow \sf \ \ \ 100 \ mL= 7 \ gm$

It means that, mass of HNO₃ present in 100 ml of solution is 7g !!

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★ Additional Information :

• The density of an object or body is equal to its total mass divided by its total volume !!

• In simple terms, density is a measure of mass per volume .

$\dag \ { \boxed{\rm { \ \rho= \dfrac{M}{V} \ }}}$

Where,

• $\rm\rho$ = density

• m = mass

• V = volume

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