Chemistry, asked by mamtadpg12, 8 months ago

A solution of hydrochloric acid is labelled as 60%(m/v) .The density of the solution is 1.1g ml-1. Calculate the concentration of the solution in %(m/m).

Answers

Answered by jaygawas2004
0

Answer:Explanation:

Answered by terabaap1292004
0

Answer:

yaa

Explanation:

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200 logs are stacked in the following manner: 20 logs in the bottom row, 200 logs are stacked in the following manner: 20 logs in the bottom row, 19 in the next row, 18 in the row next to it and so 200 logs are stacked in the following manner: 20 logs in the bottom row, 19 in the next row, 18 in the row next to it and so on (see Fig. ). In how many rows are the 200 logs placed and how many logs are in the top row?

(see Fig. ). In how 200 logs are stacked in the following manner: 20 logs in the bottom row, 19 in the next row, 18 in the row next to it and so on (see Fig. ). In how many rows are the 200 logs placed and how many logs are in the top row?

rows are the 200 logs placed and how many logs are in the top row?

in the next row, 18 in the row next to it and so on (see Fig. ). In how many rows are the 200 logs placed and how many logs are in the top row?

200 logs are stacked in the following manner: 20 logs in the bottom 200 logs are stacked in the following manner: 20 logs in the bottom row, 19 in the next row, 18 in the row next to it and so on (see Fig. ). In how many rows are the 200 logs placed and how many logs are in the top row?

, 19 in the next row, 18 in the row next to it and so on (see Fig. ). In how many rows are the 200 logs placed and how many logs are in the top row?

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