a solution of iron felain and copper solution how to separate each other
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Answer:
This is not a geological question, but from my konwledge of inorganic chemistry I can suggest something very simple indeed: dissolve the galena-chalcopyrite ore in HOT hydrochloric acid thouroughly. The solution will contain FeCl2, CuCl2 and PbCl2 (poisonous and bad smelling hydrogen sulphide will be emitted, and care should be taken). When the solution cools off, PbCl2 will precipitate inmediatly, as it is soluble only in warm water, and so the remaining solution will contain only FeCl2 and CuCl2. Filter this solution, now devoid of Pb, and treat it with sulphuric acid, the result is a solution of FeSO4 and CuSO4 (this should be done under strict conditions of security as the result of the reaction will be gaseous HCl, that is hydrogen chloride, also poisonous and highly corrosive). Ferrous sulphate is unstable in an oxidizing environment, and soon reverts to Fe hydroxides which precipitate (it's the same same reaction which forms goethite gossans on top of sulphide deposits, by the way). Hence the remaining solution will have only CuSO4, which is highly soluble in an acid and oxydizing conditions. This way you have separated Pb, Cu and Fe. You can ask a chemist about the proper concentration of the acids to be used, but the separation of the three metals can be done easily with these reactions.