Chemistry, asked by jishancute014, 11 months ago

A solution of KOH is 5.6. % by w.t. find the mole fraction of each compound

Answers

Answered by AshokKumarPanda
0

Answer: It means 5.6g of KOH is present in 100g of solution.

no. of moles of KOH= 5.6/56 = 0.1

No. of moles of water = 94.4/ 18 =5.24

Mole fraction of KOH = 0.1/0.1+5.24

= 0.1/5.34 =0.018

Mole feaction of water= 5.24/5.34=0.98

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