Question

A solution of metal ion when treated with ki gives a red precipitate which dissolves in excess ki to give a colourless solution. Moreover, the solution of metal ion on treatment with a solution of cobalt(ii) thiocyanate gives rise to a deep blue crystalline precipitate. The metal ion is

Answer 1

From the given conditions, the metal ion is identified as $Hg^{2+}$.

Explanation:

• As per the given condition which states that metal ion on reaction with KI, gives red precipitate, the ion is inferred as $Hg^{2+}$.
• It is because the only metal ion which gives a red precipitate with KI is $Hg^{2+}$ as it forms a red color substance called mercury iodide.
• The chemical equation involved in the reaction is as follows:

$Hg_2+KI\rightarrow HgI_2$

• When mercury iodide is treated with more KI solution, the red precipitate disappears due to the formation of a compound called potassium tetraiodomercurate.
• The chemical equation involved is as follows:

$HgI_2+KI \rightarrow K_2HgI_4$

• When Hg is treated with solution of cobalt(ii) thiocyanate gives rise to a deep blue crystalline precipitate due to the formation of a compound called mercury thiocyanate.
• The chemical equation involved in the reaction is as follows:

$Hg+(SCN)_2\rightarrow Hg(SCN)_2$

• Thus from the above-given chemical reactions, the metal ion is identified as $Hg^{2+}$.

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