Question

A solution of mgso4 is electrolysed for 20 min with a current of 1.5 ampere. What mass of magnesium is deposited at the cathode

Answer 1

Answer:

Mass of magnesium deposited at the cathode is 0.226 g.

Explanation:

Given data:

Time taken to electrolyse a solution of MgSO₄, t = 20 minutes = 20 * 60 sec = 1200 seconds

Current, I = 1.5 A

To find: Mass of magnesium deposited at the cathode

Atomic mass of magnesium = 24.305

Faraday's constant, F = 96500 C/mol

Using Faraday’s Law of Induction,

W = Zit …… (i)

Where,  

W = mass of the magnesium deposited at the cathode

Z = electrochemical equivalence = (atomic mass of magnesium) / (nF)

Substituting value in eq. (i), we get

W = [24.305 / 2*96500] * 1.5 * 1200 = 43749/193000 = 0.226 g

Hope this helps!!!!

Answer 2

Answer:

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