Question

a solution of MgSO4 is electrolyte for 10 min with a current of mass 5 A . what is the mass of Mg deposited​

Answer 1

Answer:

Mass of magnesium deposited at the cathode is 0.226 g.

Explanation:

Given data:

Time taken to electrolyse a solution of MgSO4, t= 20 minutes= 20*60 sec= 1200 seconds

Current, I = 1.5 A

To find: Mass of magnesium deposited at the cathode.

Atomic mass of magnesium= 24.305.

Faraday's constant, F= 96500 C/mol

Using Faraday's Law of induction,

W= Zit......... (i)

Where,

W= mass of the magnesium deposited at the cathode

Z= electrochemical equivalence= ( atomic mass of magnesium0) / (nF)

Subsituting value in eq. (i), we get W= [24.305/2*96500]*1.5*1200=

43749/193000= 0.226 g

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