A solution of na2so4 in water is electrolysed using inert electrodes. the product at cathode and anode are
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H + + 2 e - ---> 2H2 Cathode because it is a reduction reaction.
2H2O --> O2 + 4e - + 4H + Anode because it is an oxidation reaction..
I hope it helps!.... it's also correct!.. I'm a 100% sure!
2H2O --> O2 + 4e - + 4H + Anode because it is an oxidation reaction..
I hope it helps!.... it's also correct!.. I'm a 100% sure!
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