Question

a solution of naoh is 4 g per litre. what volume of HCl gas at STP will neutralise, 50 ml of the alkali solution?
1- 224 ml
2- 112 ml
3- 11200 ml
4-22.4 ml

Answer 1

Answer:

Option (2) 112 mL

Explanation:

The balanced chemical reaction is

NaOH + HCl → NaCl + H₂O

In 1 Litre, the NaoH = 4gm

or in 1000 ml, the NaOH = 4 gm

Therefore in 50 ml, NaoH = 0.2 gm

Moles of NaOH = Weight (gm)/Molecular Weight

                          = 0.2/40 = 0.005 mole

From the reation

1 mole of NaOH will neutralise 1 mole of HCl

Therefore 0.005 mole of NaCl will neutralise 0.005 mole of HCl

Volume of 1 mole of HCl is 22.4 litres at STP

Therefore volume of 0.005 moles of HCl is 0.005 x 22.4

= 0.112 Litre = 112 mL

Answer 2

Answer:

112 ml

please mark me as brainliest is