a solution of NaOH(molar mass 40g mol-1 )was prepared by dissolve in 1.6g of NaOH in 500cm3 of water calculate molarity of NaOH solution
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Molarity(M) = w × 1000 / GMW × V
where,
w = given weight of the solute = 4g
GMW = Gram Molecular Weight of the solute = 40g
V = Volume of the solution in ml. = 250 ml
So,
M of NaOH
= 4 × 1000 / 40 × 250
= 0.4 M
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2
ANSWER
1 mol of NaOH has a mass of 40g. So
Moles of NaOH=1.6g of NaOH×
1 mol NaOH/ 40g NaOH =0.04 mol NaOH
Litres of solution =500ml solution ×
1L Solution/1000ml Solution =0.5 L Solution
Molarity = moles of Solute/litres of solution
= 0.04 /0.5 mol/L
=0.08 mol/L
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