Question

A solution of nickel sulphate in which nickel rod is dipped is diluted 10 times the reduction potential of Ni at 298k

Answer 1

Explanation:

Given :-

The Kinetic energy of 1.375 × 10⁻²⁵ J

To Find :-

Calculate the wavelength

Solution :-

We know that

$\sf \lambda = \dfrac{h}{\sqrt{2\times m\times KE}}$λ= 2×m×KE h

m = 9.31 × 10⁻³¹

$\sf :\implies \dfrac{6.62\times10^{-34}}{\sqrt{2\times9.31\times 10^{-31}\times 1.375\times 10^{-25}}}$:⟹

2×9.31×10

−31

×1.375×10

−25

6.62×10

−34

$\sf :\implies \dfrac{6.62\times 10^{-34}}{\sqrt{25.6025\times 10^{-31-25}}}$:⟹

25.6025×10

−31−25

6.62×10

−34

$\sf :\implies \dfrac{6.62\times 10^{-34}}{\sqrt{25.6025\times 10^{-56}}}$:⟹

25.6025×10

−56

6.62×10

−34

$\sf :\implies \dfrac{6.62\times 10^{-34}}{5.05\times10^{-40}}$:⟹

5.05×10

−40

6.62×10

−34

$\sf :\implies \dfrac{6.62\times10^{-34}\times10^{40}}{5.05}$:⟹

$\sf :\implies 1.31 \times10^{-6}\;m:⟹1.31×10−6m$