Question

A solution of oxalic acid (COOH)2 2H2O is prepared by dissolving 0.63g of the acid in 250cm3 of the solution. Calculate the (a) molarity (b) normality of the solution..

Answer 1

Answer:

Final Answer : Molarity : 0.02M

Normality : 0.04N

Steps:

1) Oxalic Acid: C2H2O4.(2H2O )

Molar Mass : 126g

Given Mass of Oxalic acid /solute = 0.63g

no. of moles of solute = 0.63/126 = 0.5 *10^(-2)

Volume of solution, V = 250cm^3 = 0.25L

=> Molarity, M

= no. of moles of solute / Volume of solution

Hence,Molarity = 0.02M

2) Since, Basicity / Valency Factor of acid is 2 .(Two ionisable H)

=> Normality =Molarity * Valency Factor

= 0.02M * 2 = 0.04N.

3) For Molality, Data is insufficient.

As We can't get Weight of solvent in solution from required data.

PLEASE MARK AS BRAINLIEST