A solution of oxalic acid is prepared by dissolving 0.63. g of the acid solution .calculate the normality of the solution.
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Volume of the solution is not mentioned. It is assumed to be 1 litre. Answer:- 1 N Explanation:- Weight of oxalic acid taken= 0.63g Molecular weight of oxalic acid dihydrate = 126 g/ mol In oxalic acid there are two acidic protons. Equivalent weight of oxalic acid = 126/2 = 63 g/ mol Number of equivalent = Weight/ equivalent Weight = 63/63 = 1 So 1 equivalent is present in 1 litre. Normality of oxalic acid = 1 N
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