Chemistry, asked by kaushikraj676, 13 days ago

A solution of pure ferric sulphate containing 0.140 g of ferric ions is treated with excess of barium hydroxide solution. Total
weight of the precipitate will be.

pls ans fast

Answers

Answered by poojapugavkar

0

Answer:

and:- 1.14

Total weight of precipitate = Fe(OH)3 + BaSO4 = 0.2675 + 0.8737 = 1.14 gm

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