A solution of sodium hydroxide is 8% weight by weight calculate molarity normality molarity. Given that density of solution is 1. 2 gram per ml
Answers
The molar masses of NaOH and water are 40 g/mol and 18 g/mol respectively.
Assume, total number of moles of NaOH and water is 1.
The mole fraction of water =1−0.02=0.98
0.02 moles of NaOH corresponds to 0.02×40=0.8 g.
The number of moles of water is 0.98.
The mass of water =0.98×18=17.64 g.
Total mass of the solution =17.64+0.8=18.44g.
The density of the solution is 1.1 kg/dm
3
or 1.1 g/mL.
The volume of the solution =
1.1
18.44
=16.76 mL.
The molarity of the solution is the number of moles of NaOH present in 1 L of solution.
∴ The molarity of the solution =
1000
16.76
0.02
=1.193M
The molality of the solution is the number of moles of NaOH present in 1 kg of water.
∴ The molality of the solution =
1000
17.64
0.02
=1.134M
Answer:
Explanation:
2.4 = molarity
Molality = 2.174