Question

A solution of sodium salt of fatty acid was
electrolysed during kolbe's reaction. The
solution left after electrolysis is
(A) Richer in NaOH
(B) Richer in H2SO4
(C)
Richer in sodium salt
(D). Only pure water​

Answer 1

Given:

A solution of the  sodium salt of fatty acid was  electrolyzed during Kolbe's reaction.

To Find:

The  solution left after electrolysis is

(A) Richer in NaOH

(B) Richer in $H_2SO_4$

(C)  Richer in sodium salt

(D) Only pure water​

Solution:

The  solution left after electrolysis is  - Richer in NaOH (A)

(Reaction mechanism is provided in the image attached)