A solution of sodium sulphate contains 92 g of Na⁺ ions per kilogram of water. The Molality of Na⁺
ions in that solution in mol kg⁻¹ is
(A) 12 (B) 4
(C) 8 (D) 16
[JEE Main 2019]
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Answer: mnmn
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The molality of solution is - (B) 4
Molality of a solution is defined by number of moles of solute per kilogram of solvent. It is expressed mathematically as -
molality = weight of solute/molecular or atomic weight of solute*weight of solvent in kilogram.
In the given question, weight of sodium ions is 92g. Molecular weight of sodium is known, which is 23g. Mass of solvent in kilogram is given in question as 1 kg.
Therefore, keeping the values in formula -
molality = 92/23*1
molality = 4m.
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