Question

A solution of sucrose is 34.2% . The volume if solution containing 1 mole of solute is??

342dm^3 3420dm^3
500dm^3 1000dm^3​

Answer 1

Mol wt. sucrose = 342.3 approx 342gms  

Therefore  as given in 100ml of solution 34.2gm of solute is present and in order to get one mole the mass of solute should be 342 gm so multiply by 10 in direct proportion on both sides ,so 1000 ml is answer

Answer 2

Answer:

The volume of solution containing 1 mole of solute is 1000 $dm^{3}$

Explanation:

The molecular formula of Sucrose is $C_{12} H_{22} O_{11}$. Therefore,

⇒ The molecular weight would be: 12 × 12 + 1 × 22 + 16 × 11 = 342 grams.

Since the solution of sucrose is 34.2%, we can safely say that, if there were to be 100 ml of solution, it would contain 34.2 per unit of sucrose.

⇒ Therefore, one mole of sucrose would be 324 grams would be contained in 1000 $dm^{3}$ of the solution by volume. We simply have to multiply the data by 10 to achieve the conclusion.

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