Chemistry, asked by gadduharjitsingh, 11 months ago

A solution of sucrose (molar mass 342 g mol-l) is prepared by dissolving
68.4 g in 1000 g of water. Find :
(i) Boiling point of solution
(ii) Freezing point of solution.
(For water Kp = 0.52 km-1 and Ky=1.86 km-1)

Answers

Answered by abdlhafeezahmed
1

Answer:

Explanation:

Mathematical Expression of Depression in Freezing point -

∆T(f)= K(f)x  m

m = molarity of solvent

K(f)= cryoscopic  constant

∆T(f)= K(f) x m

(1.86 x 68.4)/ 342

= 0.372 degrees celcius

so, - 0.372 degrees

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