A solution of sucrose (molar mass 342 g mol-l) is prepared by dissolving
68.4 g in 1000 g of water. Find :
(i) Boiling point of solution
(ii) Freezing point of solution.
(For water Kp = 0.52 km-1 and Ky=1.86 km-1)
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Answer:
Explanation:
Mathematical Expression of Depression in Freezing point -
∆T(f)= K(f)x m
m = molarity of solvent
K(f)= cryoscopic constant
∆T(f)= K(f) x m
(1.86 x 68.4)/ 342
= 0.372 degrees celcius
so, - 0.372 degrees
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