Question

A solution of sulphuric acid having 0.49g of its dissolve in 250cmcube of solution will have its molarity. ​

Answer 1

Answer:

Molarity = 0.02

Explanation:

Given

Mass of Sulphuric acid= 0.49 g

Volume of Solution = 250 cm cube= 0.25 L

Molarity (M) = $\frac{Moles of Solute}{Total volume of Solution}$

Now, no of. moles  of Sulphuric Acid = $\frac{Mass of Sulphuric Acid (H_{2}SO_{4}) }{Molecular mass of H_{2}SO_{4} }$

= 0.49/98= 0.005

Therefore, M = 0.005/0.25

or M = 0.02

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