Question

a solution of the 0.5 mol/litr of cacl2 then no of chloride ions in 500ml of solution ​

Answer 1

For every 1 mol of CaCl2, there are 2 mol of Cl-.

In 500ml of given solution, there will be 0.25 mol CaCl2. (0.5*0.5)

So if we are looking at Cl- ions, it will be twice of that 0.25*2=0.5 mol

Answer 2

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