Question

a solution of urea in water is 3000 ppm by weight if density of this solution is 1.04g/mL determine the molar strength of the solution

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Answer 1

Answer:

30%(w/v) of urea means 30g pf urea in 100ml of solution.

Weight Of solution Is=Volume Of solution × Density of Solution.

Weight Of Solution=100×1.2=120g

Now, weight of solvent=weight of solution-weight of solute

So, weight of solvent=120–30=90g

Hope it helped u !!

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Answer 2

The molar strength of the solution is 0.052M.

Given:

A solution of urea in water is 3000 ppm by weight if the density of this solution is 1.04g/mL.

To Find:

The molar strength of the solution.

Solution:

To find the molar strength we will follow the following steps:

As we know,

Molar strength is calculated as the number of moles divided by the volume of the solution in litres.

Mass of solution of urea in ppm = 3000ppm

It is represented as:

$ppm = \frac{mass \: of \: the \: component}{mass \: of \: the \: solution} \times {10}^{6}$

Also,

$Density = \frac{mass}{volume}$

Volume is taken as 1litre = 1000ml.

mass of solution = volume× density = 1000 × 1.04 = 1040grams.

Now,

Putting the value of mass in the above equation we get,

Mass of the component =

$\frac{mass \: of \: the \: solution \: in \: ppm \times mass \: of \: the \: solution \: }{ {10}^{6} }$

$= \frac{1040 \times 3000}{ {10}^{6} } = 3.12grams$

Now,

Molar strength =

$\frac{given \: mass}{molecular \: mass \: \times \: volume \: in \: litre} = \frac{3.12}{60 \times 1} = 0.052 \: moles \: per \: litre$

Henceforth, the molar strength of the solution is 0.052M.

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