Question

A solution of weak acid (HA) was titrated
with base NaOH. The equivalence point was
reached when 36.00 mL of 0.1 M NaOH have
been added. Now 27.00 mL of 0.1 M HCI
was added to the titrated solution, the pH
was found to be 5.5229. the pK, of acid is:
(log3= 0.4771)​

Answer 1

Answer:

6

Explanation:

so milimoles of NaOH will be 3.6 =m.eq of NaA

and m.eq of HCl =2.7

check the rest in the pic attached

p.s its pKa + log 0.9/2.7

Answer 2

Answer:

Hello fellow Narayana student

Explanation:

i know you are one.