Question

A solution of zinc chloride is added to a solution of potassium sulfide and a precipitate forms

Answer 1

Explanation:

ZnCl2 + K2S ----> 2KCl + ZnS

Answer 2

A solution of zinc chloride is added to a solution of potassium sulfide and a precipitate forms to form an insoluble solid (ZnS).

When zinc chloride (ZnCl2) is added to a solution of potassium sulfide (K2S), the two compounds react in an aqueous medium. Both of these compounds are soluble in water, so they exist as ions in solution:

ZnCl2(aq) → Zn2+(aq) + 2Cl-(aq)

K2S(aq) → 2K+(aq) + S2-(aq)

When these two solutions are mixed, the positively charged zinc ions (Zn2+) combine with the negatively charged sulfide ions (S2-) to form an insoluble solid, zinc sulfide (ZnS):

Zn2+(aq) + S2-(aq) → ZnS(s)

Since zinc sulfide is insoluble in water, it forms a solid that appears as a white precipitate, which can be separated from the remaining solution.

The other product of the reaction is potassium chloride (KCl), which remains in the solution as potassium and chloride ions:

2K+(aq) + 2Cl-(aq) → 2KCl(aq)Overall, the reaction can be written as:

ZnCl2(aq) + K2S(aq) → ZnS(s) + 2KCl(aq)

This is a double displacement or precipitation reaction, where the positive ions of one compound (Zn2+) combine with the negative ions of the other compound (S2-) to form an insoluble solid (ZnS), which precipitates out of solution. The other product (KCl) remains in the solution.

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