A solution prepared by dissolving 1.25 g of oil of winter green ( methyl salicylate) in 99.0 g of benzene has a boiling point 80.31°c. determine the molar mass of this compound. (b.p. of pure benzene is=80.10°c and kb for benzene = 2.53°c kg mol-1)
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Answer:
ΔT
b
=K
p
×molality
⇒80.31−80.10=2.53×
99
M
1.25
×100
⇒0.21=2.56×
99M
1250
⇒M=
99×0.21
2.53×1250
=152gmmol
−1
Hence the molar mass of this compound is 152gmmol
−1
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