Question

A solution question 23gm of ethanol 72gm of water.calculate the mole fraction of ethanol and water

Answer 1

Answer:

Explanation:

Given conditions ⇒

Mass of the Methanol = 60 g.

Molar mass of the Methanol = 32 g/mole.

∵ No. of moles of Methanol =  

Molar Mass

Mass

​

 

∴ No. of moles = 60/32

 = 1.875 mole.

Mass of the Water = 120 g.

Molar mass of the water = 18 g/mole.

∴ No. of moles of Water =  

Molar mass

Mass

​

.

  = 120/18

  = 6.67 mole.

Now, Total number of moles in a solution = No. of moles of Methanol + No. of moles of water.

= 1.875 + 6.67

=  8.545 moles.

Now,  

Mole Fraction of Methanol in the solution =  

Total number of moles in a solutions

No. of moles of Methanol

​

.

= 1.875/8.545

= 0.22

Mole Fraction of Water in the solution =  

Total number of moles in a solution

No. of moles of water

​

.

= 6.67/8.545

= 0.78

Answer 2

Answer:

mole fraction of the component = number of moles of the compone nttotal number of moles of all the component Number of moles = mass of the component molar mass

Therefore,

Molar mass of methyl alcohol

(CH30H) = 32gmol -1

Number of moles of methyl alcohol ( CH30H) = 32 gmol-1 number of moles of methyl alcohol= 603 = 1.875 mol similarly molar mass of water = 18 gmol-1

Number of moles of water = 12018 = 6.67 mol

Now mole fraction of methyl alcohol 1.8758.542

=0.2105

mole fraction of water = 6.678.542

=0.781

This is the model for your answer